Keeping the velocity of projection constant,
the angle of projection is increased from 0°
to 90°. Then the maximum height of the
projectile
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2
90° is the correct answer. Hope it helps you!
Answered by
3
the horizontal range depends is proportional to sin2θ , where θ is the projection angle. Thus for θ =45 degrees the horizontal range is maximum as sin90 degrees =1
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