Question

Keisha is catering a luncheon. She has​ $30 to spend on a mixture of Cheddar cheese and Swiss cheese. How many pounds of cheese can Keisha get if she buys only Cheddar​ cheese? Only Swiss​ cheese? A mixture of both​ cheeses? What linear equation in standard form can she use to model the​ situation?

Answer 1

Answer:

if she has to buy from a mixture of both the cheeses then equation will become;

N x C + M x S = 30

Explanation:

Let C represents the value of cheddar cheese per pound

Let S represents the value of swiss cheese per pound.

Equation when she only buys cheddar cheese will be;

N x C = 30,

Here N is the number of pounds of cheddar cheese

Equation when she only buys swiss cheese will be;

M x S = 30,

Here M is the number of pounds of swiss cheese

Now if she has to buy from a mixture of both the cheeses then equation will become;

N x C + M x S = 30

Answer 2

Answer:

If she buys only​ Cheddar, and she spends all ​$30, she can buy

10 pounds.

If she buys only​ Swiss, and she spends all ​$30, she can buy

6 pounds

If she buys a mixture of both​ cheeses,

there are many possible amounts

that she could buy.

The equation that models the amounts is

3 x + 5 y = 30​, where x is the pounds of Cheddar and y is pounds of Swiss.

Explanation:

Cheddar: Your going to divide the amount of money she has by how much the cheese cost per pound, do 30 divided by 3 and you will get 10 pounds.

Swiss: Your going to divide the amount of money she has by how much the cheese cost per pound, do 30 divided by 5 and you will get 6.

How I got 3x+5y=30, In the beginning we did not know how many pounds she could buy with the cheddar cheese so cheddar is your X variable, Same with the Swiss cheese, so that would be your Y variable, and have it equal your total amount of money.