Math, asked by wifistudyjjn, 1 month ago

Keith and Kevin started bicycling from the corner of Monga and Bayabas streets At a particular time, Keith had covered 12 meters and Kevin 5 meters. How far apart were they at that time?​

Answers

Answered by RvChaudharY50
2

Given :- Keith and Kevin started bicycling from the corner of Monga and Bayabas streets At a particular time, Keith had covered 12 meters and Kevin 5 meters. How far apart were they at that time ?

Answer :-

we know that, According to pythagoras theorem,

  • (Hypotenuse)² = (Base)² + (Perpendicular)² .

since both Keith and Kevin started started at same point from the corner of Monga and Bayabas streets .

so,

→ Distance between them after a particular time = √(12² + 5²) = (144 + 25) = √(169) = 13 m (Ans.)

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Answered by yasminebabar
0

Given :- Keith and Kevin started bicycling from the corner of Mangga and Bayabas streets At a particular time, Keith had covered 12 meters and Kevin 5 meters. How far apart were they at that time ?

Answer :-

we know that, According to pythagoras theorem,

(Hypotenuse)² = (Base)² + (Perpendicular)² .

since both Keith and Kevin started started at same point from the corner of Monga and Bayabas streets .

so,

→ Distance between them after a particular time = √(12² + 5²) = (144 + 25) = √(169) = 13 m (Ans.)

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