Math, asked by dishu487, 9 months ago

Kelly requires 36% to pass. She gets 196 marks and falls short by 20 marks. Find the maximum numbers she could have got.​

Answers

Answered by 456tre
2

Answer:

600

Step-by-step explanation:

Let total marks be x.

Let total marks be x.Pass marks=196+20=216

Let total marks be x.Pass marks=196+20=216A.T.Q,

Let total marks be x.Pass marks=196+20=216A.T.Q,216=36% of x

Let total marks be x.Pass marks=196+20=216A.T.Q,216=36% of x=216=36/100*x

Let total marks be x.Pass marks=196+20=216A.T.Q,216=36% of x=216=36/100*x=216=36x/100

Let total marks be x.Pass marks=196+20=216A.T.Q,216=36% of x=216=36/100*x=216=36x/100=216*100=36x

Let total marks be x.Pass marks=196+20=216A.T.Q,216=36% of x=216=36/100*x=216=36x/100=216*100=36x=21600=36x

Let total marks be x.Pass marks=196+20=216A.T.Q,216=36% of x=216=36/100*x=216=36x/100=216*100=36x=21600=36x=x=21600/36

Let total marks be x.Pass marks=196+20=216A.T.Q,216=36% of x=216=36/100*x=216=36x/100=216*100=36x=21600=36x=x=21600/36=x=600

Similar questions