Math, asked by uu6662345, 28 days ago

Kelvin's Age 5 years ago is half his age 10 years hence. find his present age.

Answers

Answered by venkataramanareddy37
2

Step-by-step explanation:

(k-5)=(k+10)/2

2k-10=k+10

k=20

Attachments:
Answered by Sauron
15

Answer:

Kelvin is presently 20 years old.

Step-by-step explanation:

Given:

Kelvin's age 5 years ago = Half his age 10 years hence

To find:

The present age

Solution :

Consider his present age as y.

His age 5 years ago = (y - 5)

His age 10 years hence = (y + 10)

According to the Question,

Kelvin's age 5 years ago = Half his age 10 years hence

⟶ 2(y - 5) = (y + 10)

⟶ 2y - 10 = y + 10

⟶ 2y - y = 10 + 10

⟶ y = 20

Kelvin's present age = 20 years

Therefore, Kelvin is presently 20 years old.

___________________

Verification:

Kelvin's age 5 years ago =

⟶ 20 - 5

⟶ 15

Kelvin's age 10 years hence =

⟶ 20 + 10

⟶ 30

15 is half of 30. It satisfies the condition of the question.

Similar questions