Question

Ken shared $3,600.00 for his three (3) sons in the ratio 2 : 3 : 4. What was the smallest share received?

Answer 1

Given :-

Ken shared $3,600.00 for his three sons in the ratio 2 : 3 : 4.

To find :-

The smallest share.

Solution :-

Given that

Total sum of the money = $3,600.00 =$3600

The ratio of the shares of his three sons

= 2:3:4

Let they be $ 2X , $ 3X and $ 4X

The sum of the shares

= 2X+3X+4X = $ 9X

According to the given problem

9X = 3600

=> X = 3600/9

=> X = 400

The value of X = $ 400

The smallest Share = $ 2X

= $ 2×400

=>$ 800

Short-cut:-

Smallest share parts = 2

Total parts = 2+3+4 = 9

Total money = $ 3600.00 = $ 3600

The smallest share

= (smallest share parts / total parts )×Total money

= (2/9)×3600

= 2×400

= $ 800

Answer :-

The smallest share is $ 800

Answer 2

Answer:

Given :-

• Ken shared $3600.00 for his three sons in the ratio of 2 : 3 : 4.

To Find :-

• What was the smallest share received.

Solution :-

Let,

$\mapsto \bf Ken's\: 1^{st}\: Son\: received =\: \ 2x$

$\mapsto \bf Ken's\: 2^{nd}\: Son\: received =\: \ 3x$

$\mapsto \bf Ken's\: 3^{rd}\: Son\: received =\: \ 4x$

According to the question :

$\bigstar$ Ken shared $3600.00 for his three sons.

So,

$\implies \bf 1^{st}\: Son + 2^{nd}\: Son + 3^{rd}\: Son =\: 3600.00$

$\implies \sf 2x + 3x + 4x =\: 3600.00$

$\implies \sf 5x + 4x =\: 3600.00$

$\implies \sf 9x =\: 3600.00$

$\implies \sf x =\: \dfrac{3600.00}{9}$

$\implies \sf\bold{\purple{x =\: 400}}$

Hence, the required shares are :

$\footnotesize \dashrightarrow \sf\bold{\red{Ken's\: 1^{st}\: Son\: received =\: \ 2x =\: \ (2 \times 400) =\: \ 800}}$

$\footnotesize \dashrightarrow \sf\bold{\red{Ken's\: 2^{nd}\: Son\: received =\: \ 3x =\: \ (3 \times 400) =\: \ 1200}}$

$\footnotesize \dashrightarrow \sf\bold{\red{Ken's\: 3^{rd}\: Son\: received =\: \ 4x =\: \ (4 \times 400) =\: \ 1600}}$

$\therefore$ The smallest share received by Ken's first son is $800 .