Math, asked by kimmy77kb, 10 months ago

Kendra has a painting canvas that is 26 inches wide by 33 inches high. She painted a red rose, which covered 30% of the canvas. What was the area of the canvas which was covered by the red rose?

Answers

Answered by Pawanpatil0108
0

Answer:

fist multiply 26into33 and then answer

Step-by-step explanation:

divide by 30into 100

Answered by wifilethbridge
3

The area of the canvas which was covered by the red rose is 257.4 sq.inches

Step-by-step explanation:

Length of canvas = 26 inches

Breadth of canvas = 33 inches

Area of canvas = Length \times Breadth = 26 \times 33 = 858 inches^2

She painted a red rose, which covered 30% of the canvas

Area of red rose =30\% \times 858

Area of red rose = \frac{30}{100} \times 858 = 257.4 inches^2

Hence  the area of the canvas which was covered by the red rose is 257.4 sq.inches

#Learn more:

The length of a rectangular field is thrice its breadth. If the area of the rectangular field is 432m. What is the length of the rectangular field?​

https://brainly.in/question/14002544

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