Kendriya Vidyalaya new Allahabad Cantt is going to organise a scout camp of national level from 30 July 2019 the participants of 25 regions are coming every region scout team consists 15 students and two escorts.
1) How many people will be there on 1st august?
2)the Vidyalaya has a huge playground for making region wise tenth they given 40 X 40 square metre area in total what will be the maximum size of each state if every tent shape will be square only?
3)How much rope will be required to make fences of each tent?
4)What is the area occupied per person?
5) During tracking activity of 6 kilometre student Ram will go to Sangam and return back up to 12 noon he estimates that he can go to the Sangam at 1.5 km per hour on average and written at half the speed this speed take into account break and rest types using RAM instrumented speed what is the latest time he can begin his walk so that he can written by 12 noon ?
6) Ram used step count software on his mobile while tracking to count his steps on his walk to Sangam he found that he was 13600 steps on return estimate average step length for his return what give your answer in centimetres
Answers
Given : Kendriya Vidyalaya new Allahabad Cantt is going to organise a scout camp of national level . During tracking activity of 6 kilometre student Ram will go to Sangam and return back up to 12 noon
To find : Number of people , Area , area per person , Step length , time by which he should leave
Solution:
participants of 25 regions are coming every region scout team consists 15 students and two escorts.
people = 25 ( 15 + 2)
= 25 * 17
= 425
Total area = 25 * 40 * 40 = 40000 m²
rope for each tent = 4 * 40 = 160 m
area occupied per person = 40000/425 = 94.1 m²
a trekking activity of 6km
=> total Distance = 6 km
One way Distance = 6/2 = 3 km
Going speed = 1.5 km/hr
Return speed = 1.5/2 km /hr
Time taken in going = 3/1.5 = 2 hr
Time taken in return = 3/(1.5/2) = 4 hr
Total Time Taken = 6 hr
To return by 12 Noon
he has to leave by 12 - 6 = 6 AM
latest by 6 AM Ram can begin his walk so that he can return by 12 noon
6km = 6000m = 6000 * 100 cm
Steps = 13600
Step length = 6000 * 100/13600 = 44.1 cm
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1) The number of people to be there on 1st august is 425
Number of region = 25 = Number of teams
Number of members in 1 team = 15 + 2 = 17 members
Total number of members = 25 × 17 = 425 members
2) The maximum size of each state if every tent shape is square is 64 m²
Area given = 40 × 40 = 1600 m²
Area for each state = 1600/25 = 64 m²
3) The rope required to make fences of each tent is 32 m.
Perimeter of square = 4a
Where, a = 8 m
Thus, perimeter of square = 4 × 8 = 32 m
4) The area occupied per person is 3.76 m²
Total number of people = 425
Total area = 1600 m²
Area occupied per person = 1600/425 = 3.76 m²
5) The latest time he can begin his walk so that he can written by 12 noon is 6 AM.
Total distance = 6 km
Going speed = 1.5 km per hour
Going distance = 3 km
Going time = 3/1.5 = 2 hours
Return speed = 1.5/2 km per hour = 0.75 km per hour
Return distance = 3 km
Return time = 3/0.75 = 4 hours
Total time travel = 2 + 4 = 6 hours
The time he begin is 6 AM, so he can return by 12 PM.
6) The average step length for his return is 22.05 cm
Number of return steps = 13600 steps
Distance traveled on returning = 3 km = 300000
Length of a step = (Distance traveled in cm)/(Total number of steps)
Length of a step = 300000/13600
∴ Length of a step = 22.05 cm