Question

KENDRIYA VIDYALAYA TAWANG
C
1 point
1. Apply Euclid Division
Algorithm in order to obtain
HCF of 2 given numbers in the
context of the given problem. A
worker needs to pack 350 kg of
rice and 150 kg of wheat in
bags such that each bag
weighs the same. Each bag
should either contain rice or
wheat. Which option shows the
correct steps to find the
greatest amount of rice/wheat
the worker can pack in each
bag?​

Answer 1

Answer :-

The greatest amount of rice/wheat the worker can pack in each bag will be HCF of 350 kg of rice and 150 kg of wheat .

Finding HCF by Euclid Division Algorithm we get,

150 ) 350 ( 2

-300

50 ) 150 ( 3

-150

0

Since we gets remainder 0 , when quotient is 50 . therefore, HCF of 350 and 150 is 50 .

hence, wr can conclude that, The greatest amount of rice/wheat the worker can pack in each bag will be 50 kg .

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Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

A worker needs to pack 350 kg of rice and 150 kg of wheat in bags such that each bag weighs the same. Each bag should either contain rice or wheat. Which option shows the correct steps to find the greatest amount of rice/wheat the worker can pack in each bag

Option : I

Step 1 : 350=2(150)+50

Step 2 : 150=3(50)+0

Step 3 : Greatest amount: 50 kg

Option : II

Step 1: 350=2(150)+50

Step 2: 150=2(50)+0

Step 3: Greatest amount: 50 kg

Option : III

Step 1: 350=2(150)+50

Step 2: 150=3(50)+0

Step 3: Greatest amount: 150 kg

Option : IV

Step 1: 350=2(150)+50

Step 2: 150=2(50)+0

Step 3: Greatest amount: 150 kg

EVALUATION

Here it is given that

A worker needs to pack 350 kg of rice and 150 kg of wheat in bags such that each bag weighs the same.

Each bag should either contain rice or wheat

Here the given weights are 350 kg and 150 kg

Now 350 > 150

We now find HCF step by step by using Euclid's division algorithm.

Step : 1

$\sf{350 = 2 \times 150 + 50}$

Step : 2

$\sf{150 = 3 \times 50 + 0}$

Step : 3

So HCF = 50

Greatest amount = 50 kg

FINAL ANSWER

Hence the correct option is

Option : I

Step 1 : 350=2(150)+50

Step 2 : 150=3(50)+0

Step 3 : Greatest amount: 50 kg

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