Question

Keshev has 34 5/12 kg of rice and 23 1/4 kg of wheat. Find the total weight carriedby him.

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Answer 1

Step-by-step explanation:

$\sf rice \: with \: him \: = \: 34 \frac{5}{12} = \frac{34 \times 12 + 5}{12} = \bf \frac{413}{12} \\ \\ \sf \: wheat \: with \: him \: = \: 23 \frac{1}{4} = \frac{23 \times 4 + 1}{4} = \bf \frac{92}{4} \\ \\ \\ \sf total \: weight \: carried \: by \: him \: = weight \: of \: rice \: + \: weight \: of \: wheat \\ \\ \sf \frac{413}{12} \: + \frac{92}{4} \\ \\ \\ \sf \frac{413 + 276}{12} \\ \\ \\ \bf \frac{689}{12} \: \: or \: \: 57.42\ kg\ of\ weight\ is\ carried\ by\ him.$

Answer 2

Answer:

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