Question

kettle rated at 2.8 KW contains a mass of 465 G of water at a temperature of 24 degree celsius the cattle is switched on for a time of 2.5 minutes. during that time 92% of the input energy is transferred to the water calculate the mass of water that is evaporated​

Answer 1

By the law of conservation of energy. energy given by heater must be equal to the sum of energy gained by water and energy lost from the lid.

Pt=ms Δθ + energy lost

1000t=2×4.2×10

3

×50+160t

840t=8.4×10

3

×50=500sec=8min 20sec

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