Question

Kevin flips a coin four times. What is the
probability that he gets heads on at least one
of the four flips?​

Answer 1

Answer:

books says its option 15/16 but i say its 1/4

what do you think?

Step-by-step explanation:

[p(H)*p(T)*p(T)*p(T)] + [p(H)*p(H)*p(T)*p(T)] + [p(H)*p(H)*p(H)*p(T)] + [p(H)*p(H)*p(H)*p(H)]

=> [1/2 * 1/2 *1/2*1/2] + [1/2 * 1/2 *1/2*1/2] + [1/2 * 1/2 *1/2*1/2] + [1/2 * 1/2 *1/2*1/2] = 4/16 => 1/4.