Question

Keyboard' can be written in how many ways if all the vowels takes up odd places.

Answer 1

Answer:

Step-by-step explanation:

Now the other 5 letters can be placed anywhere (without restriction)on the remaining places. No of ways to arrange the remaining 5 letters=5!=120 ways. So total no of words = Answer to the problem = 4*6*120=2880 words.

Answer 2

Total number of such possible words is 2880

Given word is : KEYBOARD

The vowels are : E O A

total words = 8

odd places are : 4

number of vowels = 3

So, one of the odd places would not have a vowel.

The number of ways we can get that empty place is 4

The number of ways to allot the remaining vowels in 3 places would be 3!

Total ways of allocating vowels = 4 * 3! =  4!

Total ways of allocating remaining numbers =  5!

Total possible cases =  4! * 5! = 2880