Question

kezang was 5 year older than his son 10 years ago. after 8 years he will be twice the age of his son. what is their present age?​

Answer 1

Answer:

here is your answer

Step-by-step explanation:

let father's age = x

son's age = y

Five years hence, age of father = x+5  

                                age of son = y+5

So (x+5) = 3(y+5)

⇒ x =3y+10

Five years ago, age of father = x-5  

                                age of son = y-5

So x-5 = 7(y-5)

⇒3y + 10 - 5 = 7y - 35

⇒ 4y = 40

⇒y = 10  <<<<<<<<son's age

  x = 3y +10 = 40 <<<<<<father's age