Question

kFind the value of k , for which the given pair of linear equations has a unique solution: 2x+ 3y-5=0 , kx- 6y -8
= 0


Kareona

Answer 1

Answer:

k ≠ - 4

Step-by-step explanation:

Given :

Equation of lines :

2 x + 3 y - 5 = 0

k x - 6 y - 8 = 0

We're asked to find value of ' k ' for unique solution :

For unique solution we know :

a₁ / a₂ ≠ b₁ / b₂

= > 2 / k ≠ 3 / - 6

= > 2 / k ≠ - 1 / 2

= > 2 × 2 ≠ - k

= > k ≠ - 4

Therefore , value of ' k ' shouldn't equal to - 4 for unique solution!

Answer 2

$\huge\underline\mathfrak{\pink{A}\blue{N}\purple{S}\orange{W}\red{E}\green{R}}$

k≠ - 4

Step-by-step explanation:

Given :

Equation :

• 2 x + 3 y - 5 = O
• kx - 6 y - 8 = O

To find:

• value of 'k' for unique solution.

We know:

a, / a2 ≠b / b2

⇉ 2/k ≠ 3 / - 6

⇉2/k ≠ - 1/2

⇉ 2 x 2 ≠ -k

⇉4 ≠ -k

⇉ k ≠ -4

Hence , value of ' k'≠ - 4 for unique solution.

$\purple{ hope \: it \: helps}$