Kg has Nacl type structure . what is the distance between k+ and F- in KF if density is 2.48g/cm3??
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Answered by
2
Answer:
2.7 A
Explanation:
Density = n x M / V×N A
The structure of NaCl is formed by repeating the face centred cubic unit cell.
Hence, n=4
Density=2.48g cm ^−3
2.48= a 3 ×6×10 23
4×58
a=5.4 A
0
Distance between K
+
and F
−
=
2
a
=2.7 A
Answered by
21
Answer:
As we know,
As we know,Density =
As we know,Density = V×N
As we know,Density = V×N A
As we know,Density = V×N A
As we know,Density = V×N A
As we know,Density = V×N A n×M
As we know,Density = V×N A n×M
As we know,Density = V×N A n×M
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48=
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K +
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F −
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F −
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F − =
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F − = 2
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F − = 2a
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F − = 2a
As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F − = 2a =2.7 A°
Explanation:
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