Question

Kg has Nacl type structure . what is the distance between k+ and F- in KF if density is 2.48g/cm3??​

Answer 1

Answer:

2.7 A  

Explanation:

Density =  n x M / V×N  A

The structure of NaCl is formed by repeating the face centred cubic unit cell.

Hence, n=4

Density=2.48g cm  ^−3

 

2.48=  a  3  ×6×10  23

 

4×58

​  

 

a=5.4 A  

0

 

Distance between K  

+

 and F  

−

 

=  

2

a

​  

=2.7 A  

Answer 2

Answer:

As we know,

As we know,Density =

As we know,Density = V×N

As we know,Density = V×N A

As we know,Density = V×N A

As we know,Density = V×N A

As we know,Density = V×N A n×M

As we know,Density = V×N A n×M

As we know,Density = V×N A n×M

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48=

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K +

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F −

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F −

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F − =

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F − = 2

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F − = 2a

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F − = 2a

As we know,Density = V×N A n×M The structure of NaCl is formed by repeating the face centred cubic unit cell.Hence, n=4Density=2.48g cm −3 2.48= a 3 ×6×10 23 4×58 a=5.4 A 0 Distance between K + and F − = 2a =2.7 A°

Explanation:

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