kg, m,
= 1.67 x 10-27
kg
Given m = 9.1 x 10-31
e = 1.6 10-1°C and G = 6.67 x 10-11 Nm² kg-
(Ans. F. / FG = 2.27 x1039)
8. Two identical metallic spheres, having unequal,
opposite charges are placed at a distance 0.90 m
apart in air. After bringing them in contact with
each other, they are again placed at the same
distance apart. Now the force of repulsion between
them is 0.025 N. Calculate the final charge on each
of them.
[CBSE D 02C)
(Ans. 1.5 x 100)
why the final charges are equal
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Answer:
the answer is 1.5 into hundred
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