Question

kg mass is dropped from a certain height, hits the ground with speed 10 ms!
D) 180
The height will be
Coro
A) 100 m
Pe migh
B) 10 m
50 m od 10. ah
A body is dropped from 1000m height, if its potential energy is 8 * 10J. What will
D) 5 m 5 sh
be its velocity on reaching the ground
A) 1410 ms
C) 1.41 ms
B) 141 ms
D) 9800 ms
At what angle the work done will be half of its maximum value
A) 0
C) 30
B) 45°
A 500N force is applied on an object and it moves with velocity 10ms! If value
power is 2500 watt. Then what will be the angle between force and displacement
C) 90°
A) 0
D) 23
B) 60°
C) erg
D) Newton
I by multiplying force and veloc
D) 60
The unit of work is
A) watt​

Answer 1

Answer:Potential energy of ball will convert to KE

SO, mgh=  

2

mv  

2

 

​  

⇒v=  

2gh

​  

=  

2×9.8×10

​  

=14 m/s

When object will pass through sand it will loose its KE to overcome the resisting force by sand.

Now Fs=  

2

mv  

2

 

​  

=98⇒F=  

0.02

98

​  

=4900N

Explanation: