Question

(ख) एक विलयन में 40 ग्राम NaOH को 50ml जल में घोला गया है।
इसकी मोलरता एवं नॉर्मलता की गणना कीजिए।
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Answer 1

Explanation:

molarity=weight×1000/molecular weight×volume(ml)

normality=molarity×no.of H+ orOH- ions

Answer 2

The molarity and normality of given NaOH solution is 20 M and 20 N respectively

Explanation:

• Calculating the molarity of solution:

To calculate the molarity of solution:, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Given mass of NaOH = 40 g

Molar mass of NaOH = 40 g/mol

Volume of solution = 50 mL

Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{40\times 1000}{40g/mol\times 50}\\\\\text{Molarity of solution}=20M$

• Calculating the normality of solution:

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Mathematically,

$\text{Normality of solution}=\frac{\text{Given mass}\times 1000}{\text{Equivalent mass}\times \text{Volume of solution (in mL)}}$

We are given:

Given mass of NaOH = 40 g

Equivalent mass of NaOH = $\frac{\text{Molecular mass}}{\text{Basicity}}=\frac{40}{1}=40g/eq$

Volume of solution = 50 mL

Putting values in above equation, we get:

$\text{Normality of solution}=\frac{40\times 1000}{40g/eq\times 50mL}\\\\\text{Normality of solution}=20N$

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