Question

khushboo weight decreased from 70kg to 56kg. Find the percentage decreased​

Answer 1

Step-by-step explanation:

Here d= 32 km R= 6400 km

weight of body at depth d is mg`

=mg(1-d/R)%

decrease in weight =( mg- mg`)/mg × 100= 32 / 6400×100 = 0.5%.

Answer 2

Step-by-step explanation:

$decrease\% = \frac{decreased\: no}{original \: no} \times 100 \\ \\ = \frac{56}{70} \times 100 \\ \\ = \frac{8}{10} \times 100 \\ \\ = 8 \times 10 \\ \\ = 80\%$

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