Question

KI + H2 So4 +MnO4 ----> KHSO4 + Mnso4 + H2o + I2

Answer 1

Explanation:

hydrogen +oxygen =h2o this is a process

Answer 2

UnBalanced equation:

$\bold {KI + H_2SO_4 + MnO_2 = I_2 + KHSO_4 + MnSO_4 + H_2O}$

Balanced equation:

$\bold{2 KI (aq) + 3 H_2SO_4 (aq) + MnO_2 (s) → I_2 (s) + 2 KHSO_4 (aq) + MnSO_4 (aq) + 2 H_2O (l)}$

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Fact:

This is an oxidation-reduction (redox) reaction:

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Reactants:

• KI— Potassium iodide
• H2SO4 – Sulfuric acid
• MnO2 – Manganese oxide

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Products:

• I2: Iodine
• KHSO4 – Potassium hydrogen sulfate
• MnSO4 – Manganese(II) sulfate
• H2O – Water

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