Question

Kiara is 5 years
younger than Ruhi.
Four years later, Ruhi
will be twice as old
as Kiara. Find their
present ages.​

Answer 1

SOLUTION

• Kiara is 5 years younger than Ruhi.

• Four years later, Ruhi will be twice as old as Kiara.

TO DETERMINE

Their present ages.

EVALUATION

Let present age of Ruhi = x

Since Kiara is 5 years younger than Ruhi

Then present age of Kiara = x - 5

Now Four years later

Age of Ruhi = x + 4 and

Age of Kiara = x - 5 + 4 = x - 1

Now it is given that Four years later, Ruhi will be twice as old as Kiara

So by the given condition

x + 4 = 2(x-1)

$\implies \sf{x + 4 = 2x - 2}$

$\implies \sf{2x - x= 4 + 2}$

$\implies \sf{x= 6}$

Present age of Ruhi = 6 years and present age of Kiara = 1 years

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Answer 2

Step-by-step explanation:

Kiara is 5 years younger than Ruhi.

Four years later, Ruhi will be twice as old as Kiara.

TO DETERMINE

Their present ages.

EVALUATION

Let present age of Ruhi = x

Since Kiara is 5 years younger than Ruhi

Then present age of Kiara = x - 5

Now Four years later

Age of Ruhi = x + 4 and

Age of Kiara = x - 5 + 4 = x - 1

Now it is given that Four years later, Ruhi will be twice as old as Kiara

So by the given condition

x + 4 = 2(x-1)

\implies \sf{x + 4 = 2x - 2}⟹x+4=2x−2

\implies \sf{2x - x= 4 + 2}⟹2x−x=4+2

\implies \sf{x= 6}⟹x=6

Present age of Ruhi = 6 years and present age of Kiara = 1 years