Question

Kiaria is 7 years older than Jay. Martha is twice as old as Kiaria. The sum of their three ages is 77

Find the ratio of Jay’s age to Kiaria’s age to Martha’s age.

Answer 1

Answer :-

• The ratio of Jay’s age to Kiaria’s age to Martha’s age is 2:3:6.

Step-by-step explanation :

To Find :-

• The the ratio of Jay’s age to Kiaria’s age to Martha’s age.

Solution :-

Given that,

• Kiaria is 7 years older than Jay.
• Martha is twice as old as Kiaria.
• The sum of their three ages is 77

Assumption: Let us assume their ages as :-

• Jay's age = x
• Kiaria's age = ( x + 7 )
• Martha's age = 2 ( x + 7 )

Also given,

• x + ( x + 7 ) + 2 ( x + 7 ) = 77,

=> x + ( x + 7 ) + 2 ( x + 7 ) = 77

=> x + x + 7 + 2 ( x + 7 ) = 77

=> x + x + 7 + 2x + 14 = 77

=> x + x + 2x + 21 = 77

=> 2x + 2x + 21 = 77

=> 4x + 21 = 77

=> 4x = 77 - 21

=> 4x = 56

=> x = 56/4

=> x = 14

The value of x is 14. Now, the ages are :-

• Jay's age. [ We assumed Jay's age as x ]

=> x

=> 14 years

• Kiaria's age. [ We assumed Kiaria's age as ( x + 7 ) ]

=> x + 7

=> 14 + 7

=> 21 years

• Martha's age. [ We assumed Martha's age as 2 ( x + 7 ) ]

=> 2 ( x + 7 )

=> 2 ( 14 + 7 )

=> 2*21

=> 42 years,

According the question,

The ratio of Jay’s age to Kiaria’s age to Martha’s age is :-

=> Jay's age : Kiaria's age : Martha's age

=> 14 : 21 : 42

=> 2 : 3 : 6

Hence,

• The ratio of Jay’s age to Kiaria’s age to Martha’s age is 2:3:6.