Math, asked by manishthacker, 10 months ago

Kim is ten years older than babu next year she will be twice as old as him how old they are now

Answers

Answered by ThinkingBoy
27

Let the age of babu be x years

Age of kim = x+10 years

In one years, age of kim = x+11

age of babu = x+1

Age of kim is twice that of babu

x+11 = 2(x+1)

x+11=2x+2

x = 9

Present age of  babu = 9 years

Present age of kim = 19 years

Answered by farheen25
6

Step-by-step explanation:

Let the age of babu be x years

Therefore, age of Kim will be = x + 10 years

After One year

Babu's age = x + 1

Kim's age = x + 11

According to Question,

Age of Kim will be twice that of babu after a year

i.e.,

x + 11 = 2 (x+1)

x + 11 = 2x + 2

x = 9

Therefore, the present ages are-

Age of Kim = x + 10

9 + 10

19 years

Age of babu= x = 9 years

After 10 years-

Age of Kim = x + 11

9 + 11

20 years

Age of babu = x + 1

10 years

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