Question

KIND is a rhombus. Diagonal KN and DI intersect at a point O such that KO=12 cm , IO=5cm. Find the measure of ON, KI , DO.​
answer please

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

ON= 12cm

KI= 13cm

DO= 5cm

Step-by-step explanation:

it is given here that KIND is a rhombus

So, all sides are equal and diagnol are perpendicular.

then KI=IN=ND=DK ( sides of rhombus)

If , KO= 12cm and IO= 5cm

KI^2=KO^2+IO^2(h^2=p^2+b^2)

KI^2= (12)^2+ (5)^2

KI^2= 144+25

KI^2= 169

KI= √169

KI= 13

Same in all these case..

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