Math, asked by jasspreetsingh7468, 3 months ago

kindly ans my this ques ​

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Answered by CLOCIPcilpa
0

Answer:

since line segment AC bisects the angle DCB and angle DAB

So, angle DAZ = angle BAC and angle DCA = angle BCA

now in triangle ADC and ABC

AC = AC ( common )

angle DAC = angle BAC

angle DCA = angle BCA

hence triangle BAC is congurant to triangle DAC ( by ASA criterion )

and AB = AD ( by CPCT )

at the first I by mistakenly send the answer half complete so sorry for that.

Answered by guptavishrut
0

Answer:

Step-by-step explanation:

(i) In ΔBAC and ΔDAC

∠DAZ=∠BAC    {AZ bisects ∠DAB}

AC=AC  {common line}

∠DZA=∠BCA    {AZ bisects ∠DCB}

So by ASA congruence criteria ΔACD≅ACB

(ii) By ASA congruence criteria ΔACD≅ACB

So,

AB=AD {C.P.C.T}

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