kindly ans my this ques
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since line segment AC bisects the angle DCB and angle DAB
So, angle DAZ = angle BAC and angle DCA = angle BCA
now in triangle ADC and ABC
AC = AC ( common )
angle DAC = angle BAC
angle DCA = angle BCA
hence triangle BAC is congurant to triangle DAC ( by ASA criterion )
and AB = AD ( by CPCT )
at the first I by mistakenly send the answer half complete so sorry for that.
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Step-by-step explanation:
(i) In ΔBAC and ΔDAC
∠DAZ=∠BAC {AZ bisects ∠DAB}
AC=AC {common line}
∠DZA=∠BCA {AZ bisects ∠DCB}
So by ASA congruence criteria ΔACD≅ACB
(ii) By ASA congruence criteria ΔACD≅ACB
So,
AB=AD {C.P.C.T}
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