Question

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A 256 Hz fork when sounded together with another fork of unknown frequency f gives 5 beats per second. After loading one prong of the second fork with a small amount of wax, the beat frequency drops to 3 beats/s. Determine the unknown frequency f?​

Answer 1

Answer:

on putting wax on tuning fork prong's its frequency decreases , as no of beats after reduction in frequency are same means that frequency of unknown fork is higher than given fork .

so frequency of unknown fork f=256+4

f=260

Answer 2

Explanation:

When two sound waves of different frequency approach your ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - a phenomenon which is called "beating" or producing beats.

Frequency of beats is =f=∣f

1

−f

2

is decreased, Unknown frequency =260 Hz