Question

kindly answer it as soon as possible

Answer 1

joined po than u have ∆opb congruent to ∆opa by (rhs criteria)

now oa/ap=tan30
so a/ap=1/√3
therefore ap=a√3 proved

Answer 2

dram a line between OP , then <AOP =30
In triangle AOP
                    tan 30 = p / b
                  1/root 3 = a / AP 
                         AP = aroot3
        hence proved