Question

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Answer 1

Given:-

• Value of π = $\dfrac{22}{7}$

To Find:-

• Area of figure in cm².

Solution:-

Here, Radius of Semicircle CB is 5 cm.

So, Area ⇒ $\dfrac{\pi r^{2}}{2}$

              ⇒ $\dfrac{\dfrac{22}{7} \times 5 \times 5}{2}$

              ⇒ 39.2 cm²

Now, Area of Square ABCD ⇒ ( side )²

                                               ⇒ ( 10 )²

                                               ⇒ 100 cm²

∵ Area of ΔAED is to be Excluded because we counted it in the square ABCD.

So, Area of ΔAED ⇒ $\dfrac{1}{2}$ × Base × Height

                               ⇒ $\dfrac{1}{2}$ × 6 cm × 8 cm

                               ⇒ 24 cm²

Now, Area of the Figure ⇒ ( Area of Semicircle CB + Area of Square ABCD - Area of ΔAED )

                                        ⇒ ( 39.2 cm² + 100 cm² - 24 cm² )

                                        ⇒ 115.2 cm²

∴ Area of the given figure in cm² = 115.2 cm².

Some Important Terms:-

• Area of Rectangle = Length × Breadth

• Area of Circle = πr²

• Area of Parallelogram = Base × Height

• Perimeter of Rectangle = 2 ( L + B )

• Perimeter of Square = 4 × Side

• Circumference ( Perimeter ) of Circle = 2πr