Kindly answer the following question without any links or hints. The number of real roots for the quadratic equation 3x 2 + 4 = 0 is 1) 0 2) 1 3) 2 4) 4
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for equation ax2+bx+c
the number of real roots are given by 3 different case of b^2-4×a×c
1) positive then 2 real roots
2) zero 1 root ie both roots are equal
3)negative 0 real roots
In this eq 3x2+4=0 b2-4×a×c is 0 -4×3×4= -48
hence 0 real roots
the number of real roots are given by 3 different case of b^2-4×a×c
1) positive then 2 real roots
2) zero 1 root ie both roots are equal
3)negative 0 real roots
In this eq 3x2+4=0 b2-4×a×c is 0 -4×3×4= -48
hence 0 real roots
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