Question

kindly answer the question. It's argent . with full steps..

Answer 1

First, in triangle ABL
angle ABL + angle LAB = Angle ALC......eq1
since Angle ALC is exterior angle of triangle ABL.

Now, in triangle ALC
Angle ACD = angel CAL + Angle ALC.....eq2

adding eq1 and eq2 we get
angle ABL + angle LAB + angle ACD= angle ALC + angle CAL + angle ALC ......eq3

since, angle ABL= angle ABC as B-L-C
and, angle LAB= angle CAL
the eq3 can be written as,
angle ABC + Angle ACD= 2× angle ALC

Answer 2

hope this hlp..........