Question

Kindly answer this prblm asap​

Answer 1

Answer is -50

Step-by-step explanation:

$\footnotesize\color{red} Given:$

a6 = -10

a10 = -26

We know that,

$\large \color{yellow} \: an = a + (n - 1)d$

Considering a6,

a6 = a+ 5 d = -10

=> a+5d = -10

--------> eq 1

Similarly,

=> a+9d = -26

--------> eq 2

Solving eq 1 and eq 2

a + 5d = -10

a + 9d = -26

(-) (-) (+)

--------------------- Subtracting

-4d = 16

=> d = -4

Substituting in eq 1

a+(-4) = -10

a= -10+6

a = -4

Now the 15th term,

a15 = a+14 d

= -4 + 14 (-4)

= -4 - 46

= -50

Hope it helps.

thank my answers

Answer 2

ANSWER:(-46)

Step-by-step explanation:

According to the A.P series,

nth term of A.P is An=a+(n-1)d

Given, A6=-10,A10=-26

a+(6-1)d=-10

a+5d=-10......eq1

a+(10-1)d=-26

a+9d=-26.....eq2

Now,eq2-eq1

(a+9d)-(a+5d)=-26-(-10)

4d=-26+10

4d=-16

d=-4

substitute d=-4 in eq1

a+5(-4)=-10

a-20=-10

a=10

15th term of the A.p is,

A15=a+(15-1)d

=10+14(-4)

=10-56

=-46