Question

Kindly answer this question...✔️✔️✔️❣️❣️​

Answer 1

2x-3 can be written as 2x-3=0

2x=3.

x=3/2

Now by substituting x value we get,

2x3/2x3/2x3/2x3/2+3/2x3/2x3/2-8x3/2x3/2-3/2+6

By cancelling numerator and denominator we get,

81/8+27/8-18-3/2+6

108/8-18-3/2+6

now by taking LCM..

108/8-144/8-12/8+48/8

-36/8-12/8+48/8

-48/8+48/8

0/8=0

Answer 2

Answer:

Hey

Happy birthday to you

Have a gr8 day

Inbox me too