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Sol : ( 1 ) x² = 5
x = √5.
As √5 is an irrational number , so x represents an irrational number.
Proof : Let √5 is a rational number equals to p/q.Where p and q are co-prime numbers.
√5 = p/q
By squaring both sides ,
( √5 )² = ( p/q )²
5 = p² / q²
p² = 5 q² -------- equation1
Since 5 is a factor of p².So, 5 is also a factor of p.
Let , p = 5 m.
By substituting the value of p in equation1 ,
( 5 m )² = 5 q²
25 m² = 5 q²
q² = 25 m² / 5
q² = 5 m²
Since , 5 is a factor of q² , so 5 is also a factor of q .
So, we got that 5 is a factor of p and q.Hence , our assumption that √5 is a rational number is wrong.So √5 is an irrational number.
Your final answer is that x represents irrational number.
2. y² = 9
y = √9
y = ±9.
So ,y = 3 and -3 .It is a rational number.
Proof : The numerators and denominators of 3 and -3 are co - prime numbers.So , it is a rational number.
3. z² = 0.04
z² = 4 / 100
z = √ ( 4 / 100 )
z = √{( 2 x 2 ) / ( 10 x 10 ) }
z = ±2 / 10
z = ±1 / 5.
So, z = 1/5 ad -1/5.
Hence , z is a rational number.
Proof : The numerator and denominator of 1 / 5 and -1/5 are co - prime numbers.So, it is a rational number.
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x = √5.
As √5 is an irrational number , so x represents an irrational number.
Proof : Let √5 is a rational number equals to p/q.Where p and q are co-prime numbers.
√5 = p/q
By squaring both sides ,
( √5 )² = ( p/q )²
5 = p² / q²
p² = 5 q² -------- equation1
Since 5 is a factor of p².So, 5 is also a factor of p.
Let , p = 5 m.
By substituting the value of p in equation1 ,
( 5 m )² = 5 q²
25 m² = 5 q²
q² = 25 m² / 5
q² = 5 m²
Since , 5 is a factor of q² , so 5 is also a factor of q .
So, we got that 5 is a factor of p and q.Hence , our assumption that √5 is a rational number is wrong.So √5 is an irrational number.
Your final answer is that x represents irrational number.
2. y² = 9
y = √9
y = ±9.
So ,y = 3 and -3 .It is a rational number.
Proof : The numerators and denominators of 3 and -3 are co - prime numbers.So , it is a rational number.
3. z² = 0.04
z² = 4 / 100
z = √ ( 4 / 100 )
z = √{( 2 x 2 ) / ( 10 x 10 ) }
z = ±2 / 10
z = ±1 / 5.
So, z = 1/5 ad -1/5.
Hence , z is a rational number.
Proof : The numerator and denominator of 1 / 5 and -1/5 are co - prime numbers.So, it is a rational number.
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Anonymous:
Why are we arguing here ?
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