Question

kindly answer this question by describing it answer

Answer 1

#540#
There ia three triangles
Triangle 1 (ADE) +Triangle 2(ADB)+Triangle 3(BDC) = 180+180+180=540

Am I Right.

Answer 2

Hy mate your answer is here,
In the triangle AED,
∠1+∠2+∠3 = 180° (angle sum property of triangle ) ............ eq.1
In the triangle ADB,
∠4+∠5+∠6 = 180 (angle sum property of triangle) ..............eq.2.
In the triangle BDC,
∠7+∠8+∠9 = 180 (angle sum property of triangle) ..............eq.3

Now,
Adding eq.1 + eq.2 + eq.3 ,
∠1+∠2+∠3+∠4+∠5+∠6+∠7+∠8+∠9 = 180+180+180

∠1+∠2+∠3+∠4+∠5+∠6+∠7+∠8+∠9 = 540°

Hope it may help you ....