Kindly balance the following chemical equation using the “oxidation number method” (in a basic medium) ![[Cr(OH)\frac{}{4}]^{-} + H\frac{}{2}O\frac{}{2} —> CrO\frac{ 2 - }{4} + H\frac{}{2}O](https://tex.z-dn.net/?f=%5BCr%28OH%29%5Cfrac%7B%7D%7B4%7D%5D%5E%7B-%7D+%2B+H%5Cfrac%7B%7D%7B2%7DO%5Cfrac%7B%7D%7B2%7D+%E2%80%94%26gt%3B+CrO%5Cfrac%7B+2+-+%7D%7B4%7D+%2B+H%5Cfrac%7B%7D%7B2%7DO "[Cr(OH)\frac{}{4}]^{-} + H\frac{}{2}O\frac{}{2} —> CrO\frac{ 2 - }{4} + H\frac{}{2}O")
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Explanation:
2(CrOH)4 + 3H2O2 + 2OH ---> 2CrO4² + 8H2O.
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