Question

kindly explain how to solve problems based on toppling effect. (class 11)
juniors don't answer =_=

Answer 1

• When a torque is applied on a body resisting change of motion (usually due to friction), the instantaneous axis of rotation shifts (usually due to shift of normal). The body topples if the instantaneous axis of rotation falls outside the body. This is shown in the attached diagram.

1. Example: A cubical block of mass m and side L rests on a rough horizontal surface with coefficient of friction μ. A horizontal force F is applied on the block as shown in the figure. If the coefficient of friction is sufficiently high so that the block does not slide before toppling, find the minimum force required to topple the block.

Solution:

Considering case 1, when minimum force is applied,

F=μN

N=mg

∴F=μmg

Now,

when the force exceeds some value, block topples

Taking ∑ moment about the toppling axis,

∑M=0 ................ Still in equilibrium

∴∑M=∑F.d⇒0=F×L−mg× 2L

∴F= 2mg

$I HOPE ITS HELPFULL :D☺️$

Answer 2

Answer:

When a torque is applied on a body resisting change of motion (usually due to friction), the instantaneous axis of rotation shifts (usually due to shift of normal). The body topples if the instantaneous axis of rotation falls outside the body. This is shown in the attached diagram.

Example: A cubical block of mass m and side L rests on a rough horizontal surface with coefficient of friction μ. A horizontal force F is applied on the block as shown in the figure. If the coefficient of friction is sufficiently high so that the block does not slide before toppling, find the minimum force required to topple the block.