Question

kindly explain step by step oxidation state of sulphur in H2SO4​

Answer 1

Answer:

In H2SO4 , hydrogen exists in its usual +1 state, and oxygen exists in its −2 state.

Let x be the oxidation number of sulfur in sulfuric acid. Then we got:

1⋅2+x−2⋅4=0.

2+x−8=0.

x−6=0.

x=6.

So, sulfur exists in the +6 state. please make me the brainliest

Answer 2

Explanation:

Let the oxidation state of S be X

In nonmetallic compound H have -1 O.S and O have -2 always in normal oxides (vary in superoxides and peroxides)

So, 2(+1) + X + 4(-2) = 0 (Total charge on a stable compound is zero)

Thus, X = 8-2 = +6 O.S

Therefore, O.S of S in H2SO4 is +6

hope this will help you