Question

Kindly give me the answers please ​

Answer 1

${\bold{\huge{\red{\underline{\green{ANSWER}}}}}}$

Let there be 1st number as x

and 2nd nuber be y

now according to question,

${\bold{\mathrm{\boxed{ x +y=9--(1)}}}}$

and

${\bold{\mathrm{\boxed{ xy=162}--(2)}}}$

now substitute the value of equation (2) in equation (1)

$x (9 - x) = 162 \\ 9x - {x}^{2} = 162 \\ - {x}^{2} - 9x - 162 =0$

$- {x}^{2} - 18x + 9x - 162 = 0$

$- x( x + 18) - 9(x + 18) \\ ( x + 18)( - x - 9)$

So the values of x are:

$x = - 18 \: and \: x = - 9$