Question

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Answer 1

Answer:

this is ur answer

Step-by-step explanation:

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Answer 2

$\large \mathfrak \red { ✤\: Given \:✤ }$

In ∆ACB, right-angled at C, AC = 5cm, BC = 12cm, <B = 25°.

$\large \mathfrak \red {✤ \: To~ find\: ✤}$

We have to find the following :-

• Name the type of triangle.
• Find the length of AB.
• Find the value of x.
• How many acute angles are there ?
• Is there any obtuse angle in the figure ?

$\large \mathfrak \red {✤ \: Solution \: ✤}$

• Name the type of triangle.

It is a right - angled triangle since one of the angles in the triangle is a right angle [90°].

• Find the length of AB.

➼AC² + BC² = AB² [By pythagoras theorem]

➼(5)² + (12)² = AB²

➼25 + 144 = AB²

➼√169 = AB

➼AB = 13cm

• Find the value of x.

➼<A + <B + <C = 180° [Angle sum property]

➼x + 25° + 90° = 180°

➼x + 115° = 180°

➼x = 180° - 115°

➼x = 65°

• How many acute angles are there ?

Acute angles are the angles with measures below 90° and above 0°. So, there are two acute angles that is, 65° and 25°.

• Is there any obtuse angle in the figure ?

Obtuse angles are angles with measures below 180° and above 90°. So, there are no obtuse angles in the figure.

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All done :)