Kindly give the correct answer.
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Nik1121:
ans is (d)
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Answered by
18
Hi didi!
Here is yr answer.....
Given,
product of zeros = -81
one of the zeros α = 3
The other zero = β
Now,
αβ= -81
3 × β = -81
β= -81/3
β = -27
Sum of the zeros = α+β
= 3 + (-27)
= 3-27
= -24
So,
αβ = -81
α+β = -24
Let's apply formula of quad. polynomial
=> k [ x² - (α+β)x + αβ ]
=> k [x² -(-24)x + (-81) ]
=> k [ x² + 24x - 81 ]
let us suppose k = 1
=> 1 (x² + 24x - 81)
=> x² + 24x - 81
Therefore,
Option (a) is correct!
Hope it helps u didi...
#BeBrainly
Here is yr answer.....
Given,
product of zeros = -81
one of the zeros α = 3
The other zero = β
Now,
αβ= -81
3 × β = -81
β= -81/3
β = -27
Sum of the zeros = α+β
= 3 + (-27)
= 3-27
= -24
So,
αβ = -81
α+β = -24
Let's apply formula of quad. polynomial
=> k [ x² - (α+β)x + αβ ]
=> k [x² -(-24)x + (-81) ]
=> k [ x² + 24x - 81 ]
let us suppose k = 1
=> 1 (x² + 24x - 81)
=> x² + 24x - 81
Therefore,
Option (a) is correct!
Hope it helps u didi...
#BeBrainly
Answered by
8
Heya!
yr answer is here....
Given,
one of the zeros a = 3
other zero = b
ab = -81
3b = -81
b = -81/3
b = -27
a+b = 3 -27 = -24
quadratic polynomial.... formula
= k [x² -(a+b)x + ab ]
= k [ x² -(-24)x + (-81)]
= k [ x² + 24x -81 ]
let k = 1
= 1 [x²+24x-81]
= x² + 24x - 81
So,
(a) is correct!
I hope my answer helped u!
@sairambandari
yr answer is here....
Given,
one of the zeros a = 3
other zero = b
ab = -81
3b = -81
b = -81/3
b = -27
a+b = 3 -27 = -24
quadratic polynomial.... formula
= k [x² -(a+b)x + ab ]
= k [ x² -(-24)x + (-81)]
= k [ x² + 24x -81 ]
let k = 1
= 1 [x²+24x-81]
= x² + 24x - 81
So,
(a) is correct!
I hope my answer helped u!
@sairambandari
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