Question

kindly help in the following questions attached above !!


!!!Solve the two or either solve the one u can answer !!!!


Thanku ..


Regards

ItzDMahika​

Answer 1

Answer:

In ∆PQR,

Q+R+P = 180°

50+30+P=180

80+P=180

P= 180-80

P = 100.

(P is the complete angle for ∆PQR)

PT is bisector

Therefore,

QPT=RPT = 50

Now,

In∆PQS,

P+Q+S = 180

P+50+90=180

P+140=180

P=180-140

P=40

Therefore,

QPS=40

Now,

QPT=QPS+SPT

50= 40+SPT

50-40=SPT

Therefore, SPT= 10°

i.e, x= 10°

please let me know if you find any difficulty.

(Also consider the angles I'm unable to add it's sign)

I hope this helps