Question

kindly help me with this question ​

Answer 1

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Answer 2

Here is ur answer:



Given: DE | | AC, DC | | AP

To prove:
$\frac{be}{ec} = \frac{bc}{cp}$

Proof: In ∆BCA and ∆BPA

DE | | AC

$\frac{be}{ec} = \frac{bd}{ad}$
_______eq1




In ∆BDC and ∆BPA


DC | | AP


$\frac{bc}{cp} = \frac{bd}{ad}$


________eq2



from eq1 nd eq2

$\frac{be}{ec} = \frac{bc}{cp}$


hence proved!
___________




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