Physics, asked by pooja999, 7 months ago

Kindly help me with this question. Thankyou.

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Answered by juhisingh7543287

Work done=q×∆v , q=4micro coulamb (4×10^-6coulamb) , work done=4×10^-6(v2-v1), W= 4×10^-6[-10-(-2)] , W= 4×10^-6(-8), W= -32×10^-6 ,W= -32 micro juole

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