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angle BCA will be 40 degree
angle ADC will be 90 degree
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Correct question :-
In the given figure AC is diameter of circle with center O. Find angle BCA and angle ADC.
Solution :
We know that :- Angle subtended by diameter on any point of circle is 90°.
Here , in the given diagram AC is the diameter and it subtends angle at points B and D.
Therefore , ∠ABC = ∠ADC =90°.....(1)
Now , we have to find out the value of ∠BCA.
In the diagram ( refer attached picture ) ABC is triangle.
∠BAC = 50° [ given in the question ]
∠ABC = 90° [ from equation (1) ]
Let ∠BCA be x° .
According to the question :-
=> x + 50°+90° = 180° [ sum of all angles of triangle = 180° ]
=> x + 140° = 180°
=> x = 180° - 140°
=> x = 40°
Therefore , ∠BCA = 40°
And, ∠ADC =90° [ from equation (1) ]
Answer :
- ∠BCA = 40°
- ∠ADC =90°
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