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Step-by-step explanation:
given,
tan theta =1/√3
then theta=60°
cosec theta=2/√3
cosec^2 theta= 4/3
sec theta =2
sec^2 theta=4
cosec^theta -sec^2 theta
______________________ ==
cosec ^2 theta + sec^2 theta
4/3-4
_____ ==
4/3+4
-8/3
____ == -1/2
16/3
-1/2 is your answer
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