Question

kindly see the attached file and evaluate it
Dont spam plz it's my humble request ​

Answer 1

( 1+ i)^3 -( 1- i)^3

1+ i^3 +3i + 3i^2 - 1+ i^3 + 3i - 3i^2

2i^3 + 6 i

2(i^2)( i) + 6 i

-2i + 6 i

4i

Answer 2

$\huge\mathbb\red{Answer\:is\:Here}$

$<b>$( 1 + i )^3 – ( 1 - i )^3

= 1 + i^3 + 3i + 3i^2 - 1 + i^3 + 3i - 3i^2

= 2i^3 + 6i

= 2 ( i^2 ) ( i ) + 6i

= -2i + 6i

= 4i

$\huge\mathbb\purple{Keep\: Asking}$