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Q1.A train takes 10 seconds to cross a pole and 20 seconds to cross a platform of length 200m. What is the length of the train?
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train (l) platform (200)
<---------------------><-------------------------------------->
|.............................|..........................................|pole
let the length of train is l meter and speed is v m/s
distance = speed×time
time = 20s
distance = (l+200) m
speed = v
l+200 = v×20 ----------------------------(1)
apply the same equation again for the pole
now
distance = l m
time = 10s
speed = v
l = 10×v
v = l/10
putting the value of v in equation (1)
l+200 = (l/10)×20
l+200 = 2l
2l-l = 200
l = 200m
so the length of the train = 200m
<---------------------><-------------------------------------->
|.............................|..........................................|pole
let the length of train is l meter and speed is v m/s
distance = speed×time
time = 20s
distance = (l+200) m
speed = v
l+200 = v×20 ----------------------------(1)
apply the same equation again for the pole
now
distance = l m
time = 10s
speed = v
l = 10×v
v = l/10
putting the value of v in equation (1)
l+200 = (l/10)×20
l+200 = 2l
2l-l = 200
l = 200m
so the length of the train = 200m
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