Math, asked by kianadz1611, 8 months ago

Kindly solve and send the solution.​

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Answers

Answered by TrishanuSIR
1

Answer:

*AREA OF TRIANGLE(FQE)

=1/2*EQ*FQ

=1/2*60*(30+50)

=2400 sq.units ..(1)

*AREA OF TRIANGLE(FPA)

=1/2*30*50

=750 sq.units. ..(2)

*AREA OF RECTANGLE(PSBA)

=PS*PA

=(PQ+QR+RS)*PA

=(50+70+10)*50

=6500 Sq.units. ....(3)

AREA OF TRAPEZIUM(EDRQ)

=1/2*(60+40)*70

=1/2*(100)*70

=3500 sq.units. ......(4)

AREA OF TRIANGLE(DRC)

=1/2*DR*RC

=1/2*40*(10+30)

=800 sq.units. .......(5)

AREA OF TRIANGLE(BSC)

=1/2(BS)(SC)

=1/2*50*30

=750 sq.units. .........(6)

*TOTAL AREA OF POLYGONAL FIELD*=

2400+750+6500+3500+800+750

=

[14700 sq.unit]

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