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Answers
Answer:
hey cutie ✨
Explanation:
here is your answer!
Given:
A driver of a car moving at 30 m/s suddenly notices a child 80m straight ahead. If the driver’s reaction time is 0.5 s and the deceleration is 8 m/s².
To find:
If the driver can avoid hitting the child.
Calculation:
Reaction time of driver is 0.5 seconds.
So, distance between car and child after the reaction time be d ;
d = 80 - (30 \times 0.5)d=80−(30×0.5)
= > d = 80 - 15=>d=80−15
= > d = 65 \: m=>d=65m
Now , deceleration is 8 m/s².
So , let the distance taken to stop be x ;
{v}^{2} = {u}^{2} + 2axv
2
=u
2
+2ax
= > {0}^{2} = {(30)}^{2} + 2( - 8)x=>0
2
=(30)
2
+2(−8)x
= > 0 = 900 - 16x=>0=900−16x
= > 16x= 900=>16x=900
= > x = 56.25 \: m=>x=56.25m
Since x < d , so the the driver can avoid hitting the child.
So, final answer:
Child will not be hit by the car.